If `g(x) =2f(2x^3-3x^2)+f(6x^2-4x^3-3) AA x in R` and `f''(x) gt 0 AA x in R` then g(x) is increasing in the interval

Let g(x)=2f(x/2)+f(2-x) and f''(x)<0 , AA x in (0,2) .Then g(x) increasing in

Let f''(x) gt 0 AA x in R and g(x)=f(2-x)+f(4+x). Then g(x) is increasing in

A function g(x) is defined g(x)=2f(x^2/2)+f(6-x^2),AA x in R such f''(x)> 0, AA x in R , then m g(x) has

The function g is defined by g(x)=f(x^(2)-2x+8)+f(14+2x-x^(2)) where f(x) is twice differentiable function, f''(x)>=0 , AA x in R .The function g(x) is increasing in the interval

h(x)=3f((x^(2))/(3))+f(3-x^(2))AA x in(-3,4) where f'(x)>0AA x in(-3,4), then h(x) is

A function g(x) is defined g(x)=2f((x^(2))/(2))+f(6-x^(2)),AA x in R such f'(x)>0,AA x in R, then mg(x) has

If g(x)=x^2-1 and gof (x)= x^2+4x+3 , then f(1/2) is equal (f (x) gt 0 AA x in R) :

If f"(x)>0 for all x in R, f'(3)=0,and g(x)=f(tan^2 x-2tan x+4),0