सिध्द कीजिए कि : ` (sec 8A-1)/(sec 4 -1) = (tan 8A)/(tan 2A)`

(sec8A-1)/(sec4A-1)=(tan 8A)/(tan2A)

Prove that (sec 8 A-1)/(sec 4A -1)=(tan 8A)/(tan 2A) .

Prove that (sec8A-1)/(sec4A-1)=(tan8A)/(tan2A)

Prove that (sec 8A-1)/( sec 4 A -1) = ( tan 8 A)/( tan 2A).

Prove that (sec 8A-1)/(sec 4A-1)=(Tan8A)/(Tan2A)

Prove that (sec8x-1)/(sec4x-1)=(tan8x)/(tan2x)

Prove that (i) (sec 8A -1)/(sec 4A -1) =(tan 8A)/(tan 2A) (ii) (cos A+ sin A)/(cos A - sin A)-(cos A-sin A)/(cos A+sin A)=2 tan 2A

Prove that : (sec 8theta - 1)/(sec 4theta - 1) = (tan 8theta)/(tan 2theta)

(sec8 alpha-1)/(sec4 alpha-1)=(tan8 alpha)/(tan2 alpha)

(sec A+tan A-1)(sec A-tan A+1)=2tan A