Particle is dropped form the height of `20m` from horizontal ground. There is wind blowing due to which horizontal acceleration of the particles becomes `6 ms^(-2)`. Find the horizontal displacement of the particle till it reaches ground.

A stone is dropped from a height of 45 m on a horizontal level ground. There is horizontal wind blowing due to which horizontal acceleration of the stone becomes 10m//s^(2) . (Take g=10m//s^(2)) . The time taken (t) by stone to reach the ground and the net horizontal displacement (x) of the stone form the time it is dropped an till it reaches the ground are respectively

A stone is dropped from a height of 45 m on a horizontal level ground. There is horizontal wind blowing due to which horizontal acceleration of the stone becomes 10m//s^(2) . (Take g=10m//s^(2)) . The time taken (t) by stone to reach the ground and the net horizontal displacement (x) of the stone form the time it is dropped an till it reaches the ground are respectively

A ball is dropped from a height of 49 m. The wind is blowing horizontally. Due to wind a constant horizontal acceleration is provided to the ball. Choose the correct statement (s).

A ball is dropped from a height of 49 m. The wind is blowing horizontally. Due to wind a constant horizontal acceleration is provided to the ball. Choose the correct statement (s).

A ball is dropped from a height of 49 m. The wind is blowing horizontally. Due to wind a constant horizontal acceleration is provided to the ball. Choose the correct statement (s).

A particle is dropped from a finite height H above the ground level under gravity . Due to air resistance acceleration of particle becomes a=g-kv in the direction of velocity. Where k= positive constant &v= speed of particle. Then which of the following graph (s) is // are possible (t_(0)= time when particle touches the ground ):

A particle is released from a certain height H = 400m . Due to the wind, the particle gathers the horizontal velocity component v_x = ay "where a "= (sqrt5)s^(-1) and y is the vertical displacement of the particle from the point of release, then find (a) the horizontal drift of the particle when it strikes the ground , (b) the speed with which particle strikes the ground.

A particle is released from a certain height H = 400m . Due to the wind, the particle gathers the horizontal velocity component v_x = ay "where a "= (sqrt5)s^(-1) and y is the vertical displacement of the particle from the point of release, then find (a) the horizontal drift of the particle when it strikes the ground , (b) the speed with which particle strikes the ground.