Home
Class 12
CHEMISTRY
Arrange the following solutions in order...

Arrange the following solutions in order of decreasing specific conductance:
(i) 0.01 M NaCl
(ii) 0.05 M NaCl
(iii) 0.1 M NaCl
(iv) 0.5 M NaCl
Resistance of a conductivity cell filled with 0.1 M KCl solution is `"80 ohm"`. The conductivity cell has a cell constant of `"1.0 cm"^(-1)`. Find out the molar conductance of the KCl solution.

Promotional Banner

Similar Questions

Explore conceptually related problems

Arrange the following solution in order of decreasing specific conductance : (i) 0.01 M NaCl (ii) 0.05M NaCl (iii) 0.1 M NaCl (iv) 0.5M NaCl Resistance of a conductivity cell filled with 0.1 M KCl solution is 80 ohm. The conductivity cell has a cell constant of 1.0 cm^(-1) . Find out the molar conductance of the KCl solution.

Arrange the following solutions in the decreasing order of specific conductance. (i) 0.01 M NaCl (ii) 0.05 M NaCl (iii) 0.1 M NaCl (iv) 0.5 M NaCl

Resistance of a conductivity cell filled with 0.02 M KCl solution is 520 Omega . Calculate the conductivity and molar conductivity of that solution. [Cell constant of the cell = 1.29 cm^(-1) ].

The resistance of 0.01 M NaCl solution at 25°C is 200 ohm.The cell constant of the conductivity cell used is unity. Calculate the molar conductivity of the solution.

The resistance of 0.01 M NaCl solution at 25°C is 200 ohm.The cell constant of the conductivity cell used is unity. Calculate the molar conductivity of the solution.

The resistance of 0.05M KCl solution at 25^@C is 100 ohm in a cell whose cell constant is 0.3765cm^(-1) . The specific conductivity of KCl solution is