Evaluate `int_0^(pi/2) (2logsinx-logsin2x)dx`

int_(0)^(pi//2) (2logsin x - log sin 2x) dx=

By using the properties of definite integrals, evaluate the integral: int_0^(pi/2) (2log sinx-logsin2x)dx

By using the properties of definite integrals, evaluate the integrals int_0^(pi/2)(2logsinx-logsin2x)dx

Prove that int_(0)^(pi//2)(2logsinx-logsin2x)dx=(pi)/(2)(log2) .

By using the properties of definite integrals, evaluate the integrals int_(0)^((pi)/(2))(2logsinx-logsin2x)dx

Evaluate int_0^(pi/2) sin^2x dx

Evaluate int_0^(-pi//2) sin x dx

Evaluate int_0^(pi/2) sin^7x dx

Evaluate : int_0^(pi/2) x sinx dx