In the figure, seg `AB||` seg `CD||` seg `EF` `AC=1.5`, `BD=10`, `DF=6` then `AE=?`

In given figure, seg AE bot seg BC, seg DF bot line BC, AE = 4, DF = 6, then find (A(DeltaABC))/(A(DeltaDBC)) .

In given figure, seg AE bot seg BC, seg DF bot line BC, AE = 4, DF = 6, then find (A(DeltaABC))/(A(DeltaDBC)) .

In the given figure, seg BE bot seg AB and seg BA bot seg AD. If BE = 6 and AD = 9, then find (A(DeltaABE))/(A(DeltaBAD)) .

In the given figure, seg BE bot seg AB and seg BA bot seg AD. If BE = 6 and AD = 9, then find (A(DeltaABE))/(A(DeltaBAD)) .

In the figure, seg DE|| side AC and seg EF|| side BA then prove that (AD)/(DB)xx(AF)/(FC)=1

In the adjoining figure , seg ML || seg BC , seg NL || seg DC. Prove that AM : AB = AN: AD .

In the following figure, seg AB_|_"seg BC, seg DC" _|_"seg BC". If AB = 2 and DC = 3, find (A(DeltaABC))/(A(DeltaDCB)).

In the adjoining figure, seg XY|| seg AC , IF 3AX=2BX and XY=9 then find the length of AC .

In the adjoining figure, seg AD bot side BC, seg BE bot side AC, seg CF bot side AB. Point O is the orthocentre. Prove that , point O is the incentre of DeltaDEF .

In the adjoining figure, seg EF abs() side AC, AB = 18, AE = 10, BF = 4. Find BC.