A normal to the curves `x^2+kx-y+2=0` at the point `P` whose abscissa is 1 is parallel to the line, `y=x`. Now answer the question.The value of `k` is equal to (A) `-3` (B) `1` (C) `0` (D) `2`

The slope of the normal to the curve y = 3x^(2) at the point whose abscissa is 2 is:

The equation of normal to the curve y=x^(3)-x^(2)-1 at the point whose abscissa is -2, is

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

Find the equation of the normal to the curve x^2+2y^2-4x-6y+8=0 at the point whose abscissa is 2.

A chord is drawn to the curve x^(2)+2x-y+2=0 at the point whose abscissa is 1, and it is parallel to the line y=x. Find the area in the first quadrant bounded by the curve,this chord and the y- axis.

Find the equation of the normal to the curve x^(2)+2y^(2)-4x-6y+8=0 at the point whose abscissa is 2 .

The normal to the curve y=x^2-x+1 drawn at the points with the abscissa x_1=0,x_2=-1 and x_3=5/2

If the tangent the curve y^(2) + 3x - 7 = 0 at the point (h,k) is parallel to the line x - y = 4 , then the value of k is

The equation of normal to the curve y=6-x^(2), where the normal is parallel to the line x-4y+3=0 is