`8 sin theta cos theta cos 2 theta cos 4 theta = `

8sin theta cos theta cos2 theta cos4 theta=sin x rArr x=

8sin theta cos theta cos2 theta cos4 theta=sin x the x=

8sin theta cos theta*cos2 theta cos4 theta=sin x rArr x=

Prove the following: 2^(3)sin theta cos theta cos2 theta cos4 theta=sin8 theta

If 8sin theta cos theta cos2theta cos4theta=sinx then x=

If cos theta =4/5 then sin^2 theta cos theta + cos^2 theta sin theta is equal to :

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

Smallest positive value of theta satisfying 8sin theta cos2 theta sin3 theta cos4 theta=cos6 theta is

Prove that ( cos theta + cos 2 theta + cos 3 theta + cos 4 theta)/(sin theta + sin 2 theta + sin 3 theta + sin 4 theta)= cot ""(5theta)/(2).

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1