AB and CD are respectively the smallest and largest sides of a quadrilateral ABCD. Show that `angleA gt angleC and angleB gt angleC`.

AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD. Show that angleA lt angleC and angleB gt angleD .

AB and CD are respec­tively the smallest and longest sides of a quadrilateral ABCD (see th e given figure). Show that angle A gt angle C and angle B gt angle D

AB and CD are respec­tively the smallest and longest sides of a quadrilateral ABCD (see th e given figure). Show that angle A gt angle C and angle B gt angle D

AB and CD are respectively the smallest and longest sides of a quadrilateral ABCD (see Fig. 7.50). Show that ∠ A > ∠ C and ∠ B > ∠ D.

AB and CD are the smallest and largest sides of a quadrilateral ABCD. Out of angleB and angleD decide which is greater.

In a Quadrilateral ABCD, angleA +angleB = 200^@ then angleC +angleD = _____

In a quadrilateral ABCD, angleA + angleC = 180^(@) , then angleB + angleD is equal to

ABCD is a quadrilateral in which AB||DC and AD=BC. Prove that angleA=angleB and angleC=angleD .

ABCD is a cyclic quadrilateral. If angleA - angleC = 20^@ , find angleC .

In squareABCD, AB is the smallest and CD is the largest side. Prove that : (i) angleB gt angleD (ii) angleA gt angle C