अभिक्रिया ` A iff B` के लिये `log_10 K` का मान होगा
`(Delta_r H_(298)^@ = -5407 kJ "mol"^(-1), Delta_r S_(298K)^@ = 10JK^(-1)"mol"^(-1) , R = 8.314 JK^(-1) "mol"^(-1) , 2.303 xx 8.314 xx 298 xx = 5705)`

Options

A. 5
B. 10
C. 95
D. 100

Answer

B

Explanation

`A iff B`
`Delta G^@ =Delta H^@ - T Delta S^@`
`Delta G^@ = 0-2.303 RT log_10 K`
`-2.303 Rtlog_10 K = Delta H^@ - T Delta S^@ ,`
`2.303 RT log_10 K = T Delta S^@ - Delta H^@`
`log_10 K = (T Delta S^@ - Delta H^@)/(2.303 RT) = (298 xx 10 + 54.07 xx 1000)/(2.303 xx 8.314 xx 298) = 10`