यदि अभिक्रिया `H_(2)(g) + 1/2 S_(2)(g) -> H_(2)S (g)` और `H_(2)(g) + Br_(2)(g) -> 2HBr (g)` के लिए साम्य स्थिरांक क्रमशः `K_(1)` और `K_(2)` हैं तो अभिक्रिया `Br_(2) (g) + H_(2)S_(g) -> 2HBr_(s) + 1/2 S_(2) (s)` के लिए साम्य स्थिरांक होंगे

Options

A. `K_(1) xx K_(2)`
B. `K_(1)//K_(2)`
C. `K_(2)//K_(1)`
D. `K_(2)^(2) // K_(1)`

Answer

C

Explanation

`K_(1) =([H_(2)S])/([H_(2)][S_(2)]^(1//2)), K_(2) =([HBr]^(2))/([H_(2)][Br_(2)])`
`K_(3) = ([HBr]^(2) xx [S_(2)]^(1//2))/([Br_(2)] xx [H_(2)S]), K_(2)/K_(1) = K_(3)`