If u is even and w is odd, what is `u+uw`?

If u is odd and w is even, what is (uw)^(2)+u ?

Let vec u, vec nu and vec w vectors that vec u + vec nu + vec w = vec 0 . If |vec u | =3, |vec nu| = 4 , and |vec w| = 5 , then vec u. vec nu + vec nu . vec w + vec w . vec u =

If u, v and w are functions of x, then show that d/(dx)(u.v.w)=(d u)/(dx)v.w+u.(d v)/(dx).w+u.v(d w)/(dx) in two ways - first by repeated application of product rule, second by logarithmic differentiation.

In Example 94, if n is even and E denotes the event of choosing even numbered urn (p(U_(i))=(1)/(n)) , then the value of P(W//E) , is

If u, v and w are functions of x, then show that (d)/(dx)(u.v.w) = (du)/(dx) v.w+u. (dv)/(dx).w+u.v(dw)/(dx) in two ways-first by repeated application of product rule, second by logarithmic differentiation.

If u, v and w are functions of x, then show that (d)/(dx)(u.v.w) = (du)/(dx) v.w+u. (dv)/(dx).w+u.v(dw)/(dx) in two ways-first by repeated application of product rule, second by logarithmic differentiation.

If u, v and w are functions of x, then show that (d)/(dx)(u.v.w) = (du)/(dx) v.w+u. (dv)/(dx).w+u.v(du)/(dx) in two ways-first by repeated application of product rule, second by logarithmic differentiation.

If u, v and w are functions of x, then show that (d)/(dx)(u.v.w) = (du)/(dx) v.w+u. (dv)/(dx).w+u.v(dw)/(dx) in two ways-first by repeated application of product rule, second by logarithmic differentiation.