" Time taken by the projectile to reach from "A" to "B" is "t" .Then the distance "AB" is equal to "

Time taken by the particle to reach from A to B is t . Then the distance AB is equal to

Time taken by the particle to reach from A to B is t . Then the distance AB is equal to

If time taken by the projectile to reach Q is T , than PQ =

If time taken by the projectile to reach Q is T , than PQ =

If time taken by the projectile to reach Q is T , than PQ =

If time taken by the projectile to reach B is T, then AB is equal to

The time taken by a particle in reaching from trough to crest in a transverse wave is -

From the top of a hill 480 m high , a projectile is fired horizontally with a speed of 96 m//s . Calculate (i) the time taken by projectile to reach the ground . (ii) the distance of the target from the hill . (iii) the velocity with which the projectile hits the ground . Take g=10ms^(-2)

For ground to ground projectile, time take by a particle to ge point O to point C is T_(1) and during the same motion time taken by the particle to ge from A to B is T_(2) then height 'h' is :

For ground to ground projectile, time take by a particle to ge point O to point C is T_(1) and during the same motion time taken by the particle to ge from A to B is T_(2) then height 'h' is :