सिद्ध कीजिए की रेखा ` 2x+ 3y =19 ` तथा ` 2x+ 3y+7 =0` रेखा ` 2x+ 3y =6` से संदूरस्थ है |

Add 2x - 3y + z , 5y - x + 7z and 3x - y - 6z.

2x + 3y-5z = 7, x + y + z = 6,3x-4y + 2z = 1, then x =

The area (in sq units) of the quardilateral formed by the lines 2x + 3y + 6 = 0, 2x - 3y + 6 = 0, 2x + 3y - 6 = 0 and 2x - 3y - 6 = 0 is

If x- 4y = 0 and x+ 2y = 24, then what is the value of (2x + 3y) /(2x-3y)? यदि x- 4y = 0 तथा x+ 2y = 24 है, तो (2x + 3y) /(2x-3y) का मान क्या है? ,

The lines x + y + z - 3 = 0 = 2x - y + 5z - 6 and x - y - z + 1 = 0 = 2x + 3y + 7z - k are coplanar then k equals

Simplify: (2x + 5y)(3x + 4y) - (7x + 3y)(2x + y)

If 5x+y=19 and x-3y=7 , then x+y=

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

If 2x + y = 23 and 4x - y = 19, find the values of x - 3y and 5y - 2x.

Simplify : ( 3y ( x - y) - 2x ( y -2x))/( 7x ( x - y) - 3 ( x ^(2) - y ^(2)))