The degree of dissociation of `PC1_(5)` `(alpha)` obeying the equilibrium, `PC1_(5)hArrPC1_(3) + C1_(2)`, is approximately related to the pressure at equilibrium by (given `alpha ltlt 1`) :

The degree of dissociation of PCl_5 (alpha) obeying the equiliberium, PCl_5 ⇌ PCl_3 + Cl_2 is approximately realted to the pressure at equilibrium by :

The degree of dissociation of N_(2)O_(4)(1) obeying the equilibrium, N_(2)O_(4) (g) hArr 2NO_(2)(g) , is approximately related to the pressure at equilibrium by :

The degree of dissociation of N_(2)O_(4)(1) obeying the equilibrium, N_(2)O_(4) (g) hArr 2NO_(2)(g) , is approximately related to the pressure at equilibrium by :

The degree of dissociation of PCl_(5) (alpha) obeying the equilibrium, PCl_(5)hArrPCl_(3)+Cl_(2) is related to the pressure at equilibrium by :

The degree of dissociation of PCl_(5) (alpha) obeying the equilibrium, PCl_(5)hArrPCl_(3)+Cl_(2) is related to the pressure at equilibrium by :

If dissociation for reaction, PC1_(5)hArrPC1_(3) + C1_(2) is 20% at 1 atm pressure. Calculate K_(c) .

Assertion: Association of an inert gas at constant pressure to dissociation equilibrium of PC1_(5) hArr PC1_(3) + C1_(2) favours forward reaction. Reason: K_(c) =(alpha^(2))/(V(1 - alpha)) for the dissociation equilibrium of PC1_(5) where alpha is degree of dissociation of PC1_(5) .