If `sinx+cosx=sqrt(y+1/y), y gt 0, x in[0,pi]`, then find the least value of x satisfying the given conditions.

If sinx+cosx=sqrt(y+1/y) for x in [0,pi] , then

If x, y in [0,2pi] then find the total number of order pair (x,y) satisfying the equation sinx .cos y = 1

If x, y in [0,2pi] then find the total number of order pair (x,y) satisfying the equation sinx .cos y = 1

If x, y in [0,2pi] then find the total number of order pair (x,y) satisfying the equation sinx .cos y = 1

If x, y in [0,2pi] then find the total number of order pair (x,y) satisfying the equation sinx .cos y = 1

If sinx+cosx=sqrt(y+1/y) for x in [0,pi] , then x=pi/4 (b) y=0 y=1 (d) x=(3pi)/4

If x^(2)+x=1-y^(2) , where x gt 0, y gt 0 , then find the maximum value of x sqrt(y) .

For each of the following differential equation find the particular solution satisfying the given condition. (e^y+1)cos x+e^y sinx dy/dx=0 when x=(pi)/6 , y=0 .

If sinx+cosx=sqrt(y+1/y) for x in [0,pi] , then (a) x=pi/4 (b) y=0 (c) y=1 (d) x=(3pi)/4