`tanalpha+tan(60^(@)+alpha)+tan(120^(@)+alpha)=3tan3alpha`

tan alpha*tan(60^(@)-alpha)*tan(60^(@)+alpha)=tan3 alpha

tanalpha.tan(60^@-alpha).tan(60^@+alpha)=tan3alpha

If alpha=(2 pi)/(7) then tan alpha tan^(7)2 alpha+tan2 alpha tan4 alpha+tan2 alpha tan4 alpha=

Prove that, tan 8alpha - tan 5 alpha - tan 3 alpha = tan 8alpha tan 5 alpha tan 3 alpha

If alpha = (2pi )/(7) , then tan alpha tan 2 alpha + tan 2 alpha tan 4 alpha + tan 4 alpha tan alpha =

Sum the series tan alpha tan (alpha+beta)+tan(alpha+beta)+tan(alpha+2beta)+tan(alpha+2beta)tan(alpha+3beta)+… to n terms

Sum the series tan alpha tan (alpha+beta)+tan(alpha+beta)+tan(alpha+2beta)+tan(alpha+2beta)tan(alpha+3beta)+… to n terms

If (cos (alpha_1- alpha_2))/(cos (alpha_1+ alpha_2)) = (cos (alpha_3+ alpha_4))/(cos (alpha_3- alpha_4)) =0 then tan alpha_1* tan alpha_2* tan alpha_3* tan alpha_4 =............

Simplify be reducing to a single term : (tan alpha - tan ( alpha - beta))/(1 + tan alpha tan ( alpha - beta))