The distance x covered by a body of 2 kg under the action of a force is related to time t as `x=t^(2)//4`. What is the work done by this force in 2 seconds ?

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

A force acts on a 2 kg object so that its position is given as a function of time as x=3t^(2)+5. What is the work done by this force in first 5 seconds ?

A force acts on a 2 kg object so that its position is given as a function of time as x=3t^(2)+5. What is the work done by this force in first 5 seconds ?

The displacement x of a body of mass 10 kg moving in one dimension under the action of a constant force is related to time by the equation t = sqrtx + 3 . Find the work done by the force in first 5 seconds.

The displacement of a body of mass 3 kg under the action of a force is s=(t^2)/(3) metre. The work done in time 2s by the same force (in J) is

The displacement x in meters of a particle of mass m kg moving in one dimension under the action of a force is related to the time t in seconds by the equation t=sqrtx+3 , , the work done by the force (in J) in first six seconds is :-

A body covers a distance of 4m under the action of force F=(17-4x)N where x is the distance in metres. The work done by the force is

The displacement x in meter of a particle of mass mkg moving in one dimenstion under the action of a force is related to the time t in second by the equation x=(t-3)^2 . The work done by the force (in joules) in first six seconds is