`2 g` hydrogen combine with `16 g` of oxygen to from water and with `6 g` of carbon to form methane. In carbon dioxide `12 h` of carbon are combined with `32 g` of oxygen. These figures illustrate the law of

5 g of hydrogen reacts with 32 g of oxygen to form moles of water

12 g of carbon reacts with 32 g of oxygen to form 44 g of carbon dioxide.

3.2 g sulphur combines with 3.2 g of oxygen, to from a compound in one set of conditions. In another set of conditions 0.8 g of sulphur combines with 1.2 g of oxygen to form another compound. State the law illustrated by these chemical combinations.

3.2 g sulphur combines with 3.2 g of oxygen, to from a compound in one set of conditions. In another set of conditions 0.8 g of sulphur combines with 1.2 g of oxygen to form another compound. State the law illustrated by these chemical combinations.

3.2 g sulphur combines with 3.2 g of oxygen, to from a compound in one set of conditions. In another set of conditions 0.8 g of sulphur combines with 1.2 g of oxygen to form another compound. State the law illustrated by these chemical combinations.

Carbon combines with oxygen to form CO and CO_2 . State the law.

6 g of carbon combines with 32 g of sulphur to form CS_(2) . 12 g of C also combine with 32 g of oxygen to form carbon dioxide. 10 g of sulphur combines with 10 g of oxygen to form sulphur dioxide. Which law is illustrated by them?

Carbon combines with oxygen to form CO and CO_2 . What is the law behind this?

Carbon and oxygen combine to from two oxides, carbon is respectively 12: 16 and 12 : 32 . These figures illustrate the :