The sum of the two angles `cot^(-1) 3 and cosec^(-1) sqrt(5)` is

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4(cot ^(-1)3+"cosec"^(-1) sqrt(5))=pi

cot^(-1)3+cosec^(-1)sqrt(5)=

cot^(-1)9 + cosec^(-1)(sqrt(41)/4)=

cot^(-1)9+cosec^(-1)(sqrt(41))/4=

4(cot^(-1)3+csc^(-1)sqrt(5))=pi

Prove that : cot^-1 3 + cosec^-1 sqrt5 = pi/4

" (3.) "cot^(-1)3+cosec^(-1)sqrt(5)=..........

cot^(-1)9+cosec^(-1)(sqrt(41))/(4)=(pi)/(4)