Suppose the sides of a triangle form a geometric progression with common ratio r. Then r lies in the interval-

Suppose the sides of a triangle from a geometric progression with conmen ratio r. Then r lies in the interval

The sides of a triangle are in geometric progression with common ratio r lt 1. If the triangle is a right-angled triangle, then r is given by

The sides of a triangle are in geometric progression with common ratio rgt1 . If the triangle is a right angled triangle, then r^(2) is given by ?

Which of the following is a geometric progression has the common ratio as sqrt2 ?

The sides of a triangle ABC are in GP.Ifr is the common ratio then r lies in the interval

For each geometric progression find the common ratio 'r' and then find a_n -3,-6,-12,-24,…

Three numbers are in an increasing geometric progression with common ratio r. If the middle number is doubled, then the new numbers are in an arithmetic progression with common difference d. If the fourth term of GP is 3 r^(2) , then r^(2) - d is equal to :

If a,b,c are the first three non-zero terms of a geometric progression such that a-2,2b and 12c forms another geometric progression with common ratio 5, then the sum of the series a+b+c+...+oo, is