Two point A and B are situated at distance 1 m and 2m form the source of an electrostatic field. The field at a distance x from the source is `E = (5)/(x^2)`. What is the potential difference between A and B?

Two points are located at a distance of 10 m and 15 m from the source of wave. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations at two points ?.

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m//s . What is the phase difference between the oscillation of two points?

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300m//s . What is the phase difference between the oscillation of two points?

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300m//s . What is the phase difference between the oscillation of two points?

Two points are located at a distance of 10 m and 15 m from the source of oscillation. The period of oscillation is 0.05 s and the velocity of the wave is 300m//s . What is the phase difference between the oscillation of two points?

Photocell is kept at distance of 1 m from the source and incident radiation .Now distance from source is changed to 2m,then….

If the electric field is given by vec(E ) = ((100)/(x^(2)))i the potential difference between points x=10m and x=20m in volts is

Electric field at a distance x from the origin is given as E =(100N-m^2//C)/x^2 . Then potential difference between the points situated at x = 10 m and x = 20m is :-