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The point diametrically opposite to th...

The point diametrically opposite to the point P (1, 0) on the circle `x^2+""y^2+""2x""+""4y-3""=""0` is

A

(-3, -4)

B

(3, 4)

C

(3, -4)

D

(-3, 4)

Text Solution

Verified by Experts

The correct Answer is:
A
The coordinates of the centre are (-1, -2). Let Q (a, b) be diametrically opposite to P. Then, mid-point of PQ is the centre of the circle.
`:. (a+1)/(2)=-1` and `(b+0)/(2)=-2 rArr a=-3` and b=-4
Hence, required point is (-3, -4).
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OBJECTIVE RD SHARMA-CIRCLES-Chapter Test
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  11. The angle between the pair of tangents from the point (1, 1/2) to the...

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  12. The intercept on line y = x by circle x^2 + y^2- 2x = 0 is AB. Find eq...

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  13. If 3x+y=0 is a tangent to a circle whose center is (2,-1) , then find ...

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  14. Locus of the middle points of chords of the circle x^2 + y^2 = 16 whic...

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  15. Two tangents to the circle x^2 +y^2=4 at the points A and B meet at P(...

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  16. A tangent is drawn to the circle 2(x^(2)+y^(2))-3x+4y=0 and it touch...

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