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The straight line 2x-3y = 1 divides the ...

The straight line 2x-3y = 1 divides the circular region `x^2+ y^2 le6` into two parts. If S = { `( 2 , 3/4) , (5/2,3/4) , (1/4,-1/4), (1/8,1/4)`}, then the number of point(s) in S lying inside the smaller part is

A

2

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
A
Points lying inside the smaller region are points satisfying
`2x-3y gt 1` and `x^(2)+y^(2)-6 lt 0`

Clearly, `(2, (3)/(4)) `and `((1)/(4), (1)/(4))` satisfy these inequations.
Hence, required number or points is 2.
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OBJECTIVE RD SHARMA-CIRCLES-Chapter Test
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