Home
Class 12
MATHS
The equation of the image of the circle ...

The equation of the image of the circle `x^2+y^2+16x-24y+183=0` by the line mirror `4x+7y+13=0` is :

A

`x^(2)+y^(2)+32x-4y+235=0`

B

`x^(2)+y^(2)+32x+4y-235=0`

C

`x^(2)+y^(2)+32x-4y-235=0`

D

`x^(2)+y^(2)+32x+4y+235=0`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    OBJECTIVE RD SHARMA|Exercise Chapter Test|55 Videos

  • CIRCLES

    OBJECTIVE RD SHARMA|Exercise Section II - Assertion Reason Type|12 Videos

  • CARTESIAN PRODUCT OF SETS AND RELATIONS

    OBJECTIVE RD SHARMA|Exercise Chapter Test|31 Videos

  • COMPLEX NUMBERS

    OBJECTIVE RD SHARMA|Exercise Chapter Test|59 Videos

Similar Questions

Explore conceptually related problems

The equation of the image ofthe circle x^(2)+y^(2)+16x-24y+183=0 by the line mirror 4x+7y+13=0 is

The equatioin of the image of the circle x^(2)+y^(2)+016x-24y+183=0 in the line mirror 4x+7y+13=0 is: a.x^(2)+y^(2)+32x-4y+235=0 b.x^(2)+y^(2)+32x-4y-235=0cx^(2)+y^(2)+32x-4y-235=0dx^(2)+y^(2)+32x-4y-235=0dx^(2)+y^(2)+32x+4y+235=0

The equation of the image of the circle x^(2)+y^(2)+16x-24y+183=0 in the mirror 4x+7y+13=0 is x^(2)+y^(2)+32x-4y+235=0x^(2)+y^(2)+32x+4y-235=0x^(2)+y^(2)+32x-4y-235=0x^(2)+y^(2)+32x+4y-235=0x^(2)+y^(2)+32x+4y+235=0

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the mirror x+y-1=0 is

Find the equation of the image of the circle x^(2)+y^(2)+8x-16+64=0 in the line mirror x=0.

Find the image of the circle x^(2)+y^(2)-2x+4y-4=0 in the line 2x-3y+5=0

The equation of the image of the curve x^(2)-y^(2)=4 with respect to the line x+y-2=0, is

The equation of the image of the lines y=|x| in the line mirror x = 2 is

The equation of a circle, which is mirror change of the circle x ^(2) + y ^(2) - 2x =0, in the line, y =3 -x is

Let the equation of circle is x^(2) + y^(2) - 6x - 4y + 9 = 0 . Then the line 4x + 3y - 8 = 0 is a

OBJECTIVE RD SHARMA-CIRCLES-Exercise
  1. Locus of the mid points of the chords of the circle x^2+y^2=a^2 which ...

    Text Solution

    |

  2. If the circles (x-a)^(2)+(y-b)^(2)=c^(2) and (x-b)^(2)+(y-a)^(2)=c^(2)...

    Text Solution

    |

  3. The equation of the image of the circle x^2+y^2+16x-24y+183=0 by the l...

    Text Solution

    |

  4. The number of the tangents that can be drawn from (1, 2) to x^(2)+y^(2...

    Text Solution

    |

  5. Equation of the circle through the origin and making intercepts of 3 a...

    Text Solution

    |

  6. If y=2x is the chord of the circle x^2+y^2-4x=0, find the equation of ...

    Text Solution

    |

  7. The tangent to x^(2)+y^(2)=9 which is parallel to y-axis and does not ...

    Text Solution

    |

  8. The two circles x^(2)+y^(2)-5=0 and x^(2)+y^(2)-2x-4y-15=0

    Text Solution

    |

  9. If the circle x^2+y^2+2x+3y+1=0 cuts x^2+y^2+4x+3y+2=0 at Aa n dB , th...

    Text Solution

    |

  10. The circle x^(2)+y^(2)=4 cuts the circle x^(2)+y^(2)-2x-4=0 at the poi...

    Text Solution

    |

  11. If the circle x^2+y^2+2gx+2fy+c=0 is touched by y=x at P such that O P...

    Text Solution

    |

  12. The number of common tangents of the circles x^(2)+y^(2)+4x+1=0 and x...

    Text Solution

    |

  13. The length of the common chord of the circles x^(2)+y^(2)-2x-1=0 and ...

    Text Solution

    |

  14. If a circle passes through the point (a, b) and cuts the circle x^2 + ...

    Text Solution

    |

  15. If the lines 3x-4y+4=0a d n6x-8y-7=0 are tangents to a circle, then fi...

    Text Solution

    |

  16. Coordinates of the centre of the circle which bisects the circumferenc...

    Text Solution

    |

  17. One of the diameter of a circle circumscribing the rectangle ABCD is 4...

    Text Solution

    |

  18. The points of contact of tangents to the circle x^(2)+y^(2)=25 which a...

    Text Solution

    |

  19. If (mi,1/mi),i=1,2,3,4 are concyclic points then the value of m1m2m3m4...

    Text Solution

    |

  20. Find the area of the triangle formed by the tangents from the point (4...

    Text Solution

    |