Two circle x^2+y^2=6 and x^2+y^2-6x+8=0 ...

Two circle `x^2+y^2=6` and `x^2+y^2-6x+8=0` are given. Then the equation of the circle through their points of intersection and the point (1, 1) is `x^2+y^2-6x+4=0` `x^2+y^2-3x+1=0` `x^2+y^2-4y+2=0` none of these

`x^(2)+y^(2)-6x+4=0`

`x^(2)+y^(2)-3x+1=0`

`x^(2)+y^(2)-4y+2=0`

none of these

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Two circle x^(2)+y^(2)=6 and x^(2)+y^(2)-6x+8=0 are given.Then the equation of the circle through their points of intersection and the point (1,1) is x^(2)+y^(2)-6x+4=0x^(2)+y^(2)-3x+1=0x^(2)+y^(2)-4y+2=0 none of these

Find the equation of the circle passing through the point of intersection of the circles x^(2)+y^(2)-6x+2y+4=0,x^(2)+y^(2)+2x-4y-6=0 and with its centre on the line y=x

The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0,x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13)" is

The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0 , x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13) is

The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0,x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13) is

The equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)+6x+4y-12=0 , x^(2)+y^(2)-4x-6y-12=0 and having radius sqrt(13) is

Find the equation of the circle through the points of interrection of the circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+6x+4y-12=0 and cutting the circle x^(2)+y^(2)-2x-4=0 orthogonally.

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