If x, F and U denote the displacement force acting on and potential energy of a particle:

If x,F and U denote the dispalcement, force acting on and potential energy of a particle then

A particle is executing SHM with amplitude A. At displacement x=(-A/4) , force acting on the particle is F, potential energy of the particle is U, velocity of particle is v and kinetic energy is K. Assuming potential energyh to be zero at mean position. At displacement x=A/2

A particle is executing SHM with amplitude A. At displacement x=(-A/4) , force acting on the particle is F, potential energy of the particle is U, velocity of particle is v and kinetic energy is K. Assuming potential energyh to be zero at mean position. At displacement x=A/2

A particle is executing SHM with amplitude A. At displacement x=(-A/4) , force acting on the particle is F, potential energy of the particle is U, velocity of particle is v and kinetic energy is K. Assuming potential energyh to be zero at mean position. At displacement x=A/2

A particle is executing SHM. At a displacement y_(1) its potential energy is U_(1) and at a displacement y_(2) its potential energy is U_(2) . The potential energy of the particle at displacement (y_(1)+y_(2)) is

The potential energy U of a body of mass m is given by U = ax + by where x and y are the position coordinates of the particle, the net force acting on the particle is:

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is