`(sin^2A- sin^2B)/( sin A cos A-sin Bcos B) =tan(A+B) `

(sin^2A- sin^2B)/( sin A cos A-sin Bcos B) = .............. A) tan (A-B) B) tan (A+B) C) cot (A-B) D) cot (A+B)

(sin^(2)A-sin^(2)B)/(sin A cos A-sin B cos B) is equal to (a) sin A cos A-sin B cos Btan(A-B)(b)tan(A+B)cot(A-B)(d)cot(A+B)

(sin ^(2) A - sin ^(2) B)/( sin A cos A - sin B cos B) is equal to

(cos 2B - cos 2 A)/( sin 2 A + sin 2 B) = tan (A -B).

(sin A + sin B) / (cos A + cos B) = tan ((A + B) / (2))

(sin2A + sin2B) / (sin2A-sin2B) = (tan (A + B)) / (tan (AB))

(sin A + sin B) / (sin A-sin B) = tan ((A + B) / (2)) cot ((AB) / (2))

Prove that (sin A-sin B)/(cos A+ cos B) = "tan" (A-B)/2

Prove that (sin2A+sin2B)/(sin2A-sin2B)=tan(A+B)/tan(A-B)

Prove that: (sin A-sin B)/(cos A+cos B)=tan((A-B)/2)