`(sec8A-1)/(sec4A-1)` is equal to (A) `(tan2A)/(tan8A)` (B) `(tan8A)/(tan2A)` (C) `(cot8A)/(cot2A)` (D) none of these

(sec 8 A-1)/( sec 4A-1)= ..................... A) (tan 2A)/( tan 8A) B) (tan 8A)/(tan 2A) C) (cot 8A)/(cot 2A) D) (tan 6A)/(tan 2A)

(sec8A-1)/(sec4A-1)=(tan 8A)/(tan2A)

Prove that (sec8A-1)/(sec4A-1)=(tan8A)/(tan2A)

Prove that (sec 8A-1)/( sec 4 A -1) = ( tan 8 A)/( tan 2A).

Prove that (sec 8A-1)/(sec 4A-1)=(Tan8A)/(Tan2A)

(sec8A+sec4A-2)/(sec8A-sec4A) is equal to (A)(tan6A)/(tan10A) (B) (cos10A)/(cos6A)(C)(sin10A)/(sin6A) (D) (tan10A)/(tan6A)

Prove that (sec 8 A-1)/(sec 4A -1)=(tan 8A)/(tan 2A) .

9sec^2A-9tan^2A is equal to (a) 1 (b) 9 (c) 8 (d) 0

Prove that (sec8x-1)/(sec4x-1)=(tan8x)/(tan2x)

9sec^(2)A-9tan^(2)A is equal to (a)1(b)9(c)8 (d) 0