If the roots of `ax^2+bx+c=0 and px^2+qx+r=0` differ by the same quantity, then `(b^2-4ac)/(q^2-4pr)`

IF ax^2 + 2bx +c=0 , and px^2 + 2 qx + r=0

If the roots of the equation ax^2+bx+c=0 differ by K then b^(2)-4ac=

Let alpha_(1),alpha_(2) and beta_(1),beta_(2) be the roots of ax^(2) + bx + c = 0 and px^(2) + qx + r = 0 respectively. If the system of equations alpha_(1)y + alpha_(2)z= 0 and beta_(1) y + beta_(2) z = 0 has a non - trivial solution, then a) b^(2) pr = q^(2) ac b) bpr^(2) = qac^(2) c) bp^(2)r = qa^(2)c d)None of these

If alpha" and "beta are the roots of ax^(2)+bx+c=0 and alpha+k, beta+k are the roots of px^(2)+qx+r=0 , then (b^(2)-4ac)/(q^(2)-4pr)=

If alpha and beta are roots of ax^(2)+bx+c=0 ,and roots differ by k then b^(2)-4ac=

If 'alpha and beta are roots of ax^(2)+bx+c=0 ,and roots differ by k then b^(2)-4ac=

If alpha , beta are the roots of ax^(2) +bx+c=0, ( a ne 0) and alpha + delta , beta + delta are the roots of Ax^(2) +Bx+C=0,(A ne 0) for some constant delta , then prove that (b^(2)-4ac)/(a^(2))=(B^(2)-4AC)/(A^(2)) .

If the roots of the equation px^(2)+qx+r=0(pne0) be equal, then q=2sqrt(pr) .

If the roots of ax^2+bx+c=0 are real and equal then.......a) b^2-4aclt0 b) b^2-4ac=0 c) b^2-4acgt0 d) Cannot say