10.[{(-(1)/(3))^(2)}^(-2)]^(-1)

The following steps are involved in finding the value of 10 (1)/(3) xx 9(2)/(3) by using an appropriate indentity . Arrange them in sequential order . (A) (10)^(2) - ((1)/(3))^(2) = 100 - (1)/(9) (B) 10(1)/(3) xx 9(2)/(3) = (10 + (1)/(3)) (10 - (1)/(3)) (C) (10 + (1)/(3)) (10 - (1)/(3)) = (10)^(2) - ((1)/(3))^(2) [because (a + b) (a -b) = (a^(2) - b^(2))] (D) 100 - (1)/(9) = 99 + 1 - (1)/(9) = 99(8)/(9)

the value of 1+(1)/(10)+(2)/(10^(2))+(2)/(10^(3))+(2)/(10^(4))......

Prove that cos^(-1) (sqrt(1/3))-cos^(-1) (sqrt((1)/(6)))+cos^(-1) ((sqrt(10)-1)/(3sqrt2))=cos^(-1) (2/3)

Prove that cos^(-1) (sqrt(1/3))-cos^(-1) (sqrt((1)/(6)))+cos^(-1) ((sqrt(10)-1)/(3sqrt2))=cos^(-1) (2/3)

If harmonic mean of numbers (1)/(2),(1)/(2^(2)),(1)/(2^(3)),............(1)/(2^(10)) is (lambda)/(2^(10)-1) then lambda is equal to

If harmonic mean of (1)/(2),(1)/(2^(2)),(1)/(2^(3)),...,(1)/(2^(10)) is (lambda)/(2^(10)-1) , then lambda=

If harmonic mean of (1)/(2),(1)/(2^(2)),(1)/(2^(3)),...,(1)/(2^(10)) is (lambda)/(2^(10)-1) , then lambda=

If harmonic mean of (1)/(2),(1)/(2^(2)),(1)/(2^(3)),...,(1)/(2^(10)) is (lambda)/(2^(10)-1) , then lambda=