When 20g of `CaCO_3` is put into a 11.45L flask and heated to `800^@C` , 35% of `CaCO_3` remains undissociated at equilibrium. Calculate the value of `K_p`.

When 20 g of CaCO_(3) were put into 10 litre flask and heated to 800^(@)C , 35% of CaCO_(3) remained unreacted at equilibrium. K_(p) for decomposition of CaCO_(3) is :

When 20 g of CaCO_3 were put into 10 litre flask and heated to 800^@C, 30% of CaCO_3 remained unreacted at equilibrium K_p for decomposition of CaCO_3 will be

When 20 g of CaCO_3 were put into 10 litre flask and heated to 800^Oc 35% CaCO_3 remained unreacted at equillibrium . Predict k_p for decomposition of CaCO_3 .

For the reaction CaCO_(3)(s) hArr CaO(s) + CO_(2)(g) K_(p)=1.16 atm at 800^(@)C . If 20.0g of CaCO_(3) was put into a 10.0 L flask and heated to 800^(@)C, what percentage of CaCO_(3) would remain unreacted at equilibrium ?

20 gm of CaCO_(3) is allowed to dissociate in a 5.6 litres container at 819^(@) C. If 50% of CaCO_(3) is dissocitated at equilibrium the 'K_(p)' value is

20 gm of CaCO_(3) is allowed to dissociate in a 5.6 litres container at 819^(@) C. If 50% of CaCO_(3) is dissocitated at equilibrium the 'K_(p)' value is

For the reaction CaCO_(3)(s) hArr CaO(s) + CO_(2)(g) was put in to 10 L container and heated to 800^(@)C , what percentage of the CaCO_(3) would remain unreacted at equilibrium. if 'k_(p)' is 1.16 atm and 'CaCO_(3)(s)' initially is 20g

For the reaction CaCO_(3)(s) hArr CaO(s) was put in to 10 L container and heated to 800^(@)C , what percentage of the CaCO_(3) would remain unreacted at equilibrium.

For the reaction CaCO_(3) (s) hArr CaO (s) + CO_(2) (g), K_(p) = 1*16 " atm . If "20* 0" g of " CaCO_(3) " is heated to " 800^(@)C" in a 10 litre container, what % of "CaCO_(3) " would remain unreached at equilibrium ? ( Mol. wt. of " CaCO_(3) = 100, R = 0*0821 " L atm mol"^(-1) K^(-1) )