Home
Class 11
PHYSICS
A particle is subjected to two simple ha...

A particle is subjected to two simple harmonic motions
`x_1=A_1 sinomegat`
`and x_2=A_2sin(omegat+pi/3)`
Find a the displacement at t=0, b. the maxmum speed of the particle and c. the maximum acceleration of the particle

Promotional Banner

Similar Questions

Explore conceptually related problems

(a) A particle is subjected to two simple harmonic motions x_1=A_1sin omegat and x_2=A_2 sin (omegat+pi//3) . Find (i) the displacement at t=0 , (ii) the maximum speed of the particle and (iii) the maximum acceleration of the particle. (b) A particle is subjected to two simple harmonic motions, one along the x-axis and the other on a line making an angle of 45^@ with the x-axis. The two motions are given by xy=x_0sinomegat and s=s_0sin omegat Find the amplitude of the resultant motion.

A partical is subjucted to two simple harmonic motions x_(1) = A_(1) sin omega t and x_(2) = A_(2) sin (omega t + pi//3) Find(a) the displacement at t = 0 , (b) the maximum speed of the partical and ( c) the maximum acceleration of the partical.

A partical is subjucted to two simple harmonic motions x_(1) = A_(1) sin omega t and x_(2) = A_(2) sin (omega t + pi//3) Find(a) the displacement at t = 0 , (b) the maximum speed of the partical and ( c) the maximum acceleration of the partical.

A particle is subjected to two simple harmonic motions x_1=A_1 sinomegat and x_2=A_2sin(omegat+pi/3) Find the maximum speed of the particle and the maximum acceleration of the particle

A particle is subjected to two simple harmonic motions. x_(1) = 4.0 sin (100pi t) and x_(2) = 3.0 sin(100pi t + (pi)/(3)) Find (a) the displacement at t = 0 (b) the maximum speed of the particle and (c ) the maximum acceleration of the particle.

A particle is subjected to two simple harmonic motions. x_(1) = 4.0 sin (100pi t) and x_(2) = 3.0 sin(100pi t + (pi)/(3)) Find (a) the displacement at t = 0 (b) the maximum speed of the particle and (c ) the maximum acceleration of the particle.

A particle is subjected to two simple harmonic motions x_(1)=4 sin(100pit) and x_(2)==3 sin ^((100pi t + (pi)/(2)) Then maximum acceleration of the particle is

A 20g particle is subjected to two simple harmonic motions x_1=2sin10t , x_2=4sin(10t+(pi)/(3)) . Where x_1 and x_2 are in metres and t is in seconds.

A particle executes two types of SHM. x_(1) = A_(1) sin omega t " and "x_(2) = A_(2) sin [omega t+(pi)/(3)] , then find the maximum speed of the particle.