A stone of mass 0.1 kg tied to one end of a string lm long is revolved in a horizontal circle at the rate of `(10)/(pi)" rev/s"`. Calculate the tension in the string.

A stone of mass 0.3 kg is tied to one end of a string 0.8 m long and rotated in a vertical circle. At what speed of the ball will the tension in the string be zero at the highest point of the circle? What would be the tension at the lowest point in this case ? Given g = 9.8 ms^(-2) ?

A stone of mass 50 g is tied to the end of a string 2 m long and is set into rotation in a horizontal circle with a uniformspeed of 2 m//s . Then tension in the string is

A stone of mass 50 g is tied to the end of a string 2 m long and is set into rotation in a horizontal circle with a uniforn speed of 2m//s .Then tension in the string is

A stone of mass 1 kg tied at the end of a string of length 1 m and is whirled in a verticle circle at a constant speed of 3 ms^(-1) . The tension in the string will be 19 N when the stone is (g=10 ms^(-1))

A stone of mass 1 kg tied at the end of a string of length 1 m and is whirled in a verticle circle at a constant speed of 3 ms^(-1) . The tension in the string will be 19 N when the stone is (g=10 ms^(-1))

Stone of mass 1 kg tied to the end of a string of length 1m , is whirled in horizontal circle with a uniform angular velocity 2 rad s^(-1) . The tension of the string is (in newton)

Stone of mass 1 kg tied to the end of a string of length 1m , is whirled in horizontal circle with a uniform angular velocity 2 rad s^(-1) . The tension of the string is (in newton)

A mass is tied to a, string 1 m long and rotated in a horizontal circle at the rate of 600 rpm. If the tension inthe string is 3943.8 N, calculate the mass.