[2tan^(2)45^(@)+cos^(2)30^(@)-sin^(2)60^(@)],[sin30^(@)+]

(5sin^(2)30^(@)+cos^(2)45^(@)-4tan^(2)30^(@))/(2sin30^(@).cos30^(@)+tan45^(@))=?

(kcosec^(2)30^(@).sec^(2)45)/(8cos^(2)45^(@).sin^(2)60^(@))=tan^(2)60^(@)-tan^(2)30^(@) , then k = ?

Show that (i) cos60^(@)*cos30^(@)-sin60^(@)*sin30^(@)=cos90^(@) (ii) cos60^(@)=1-2sin^(2)30^(@)=2cos^(2)30^(@)-1 (iii) (tan60^(@)-tan30^(@))/(1+tan60^(@)*tan30^(@))=tan30^(@)

2tan ^ (2) 45 ^ (@) - + cos ^ (2) 30 ^ (@) - sin ^ (2) 60 ^ (@) is

Evaluate : (i) sin^(2)30^(@)-2cos^(3)60^(@)+3tan^(4)45^(@) (ii) (cos0^(@)+sin45^(@)+sin30^(@))(sin90^(@)-cos45^(@)+cos60^(@))

Find the value of (4sin^(2)60^(@)-cos^(2)45^(@))/(tan^(2)30^(@)+sin^(2)0^(@))

Evaluate the following : (5cos^(2)60^(@)+4sec^(2)30^(@)-tan^(2)45^(@))/(sin^(2)30^(@)+cos^(2)30^(@))

If x sin 45^(@) cos^(2)60^(@)=(tan^(2)60^(@) cosec 30^(@))/(sec 45^(@) cot^(2) 30^(@)) then x