A particle of mass 0.5 kg executes SHM. If its period of oscillation is `pi` seconds and total energy is 0.04 J, then the amplitude of oscillation will be

The frequency of oscilation is ((10)/(pi)) (in Hz) of a particle of mass 0.1 kg which executes SHM is 0.2J at position x = 0.02m . The potential energy is zero at mean position Find the amplitude of osclllation (in meter) :

A particle of mass 0.1kg executes SHM under a force F =- 10x (N) . Speed of particle at mean position is 6 m//s . Find its amplitude of oscillation.

A particle of mass 0.1kg executes SHM under a force F =- 10x (N) . Speed of particle at mean position is 6 m//s . Find its amplitude of oscillation.

Amplitude of a particle of mass 0.1 kg executing SHM is 0.1 m. At the mean position its kinetic energy is 8xx10^(-3)J . Find the time period of its vibration.

If the potential energy of a harmonic oscillator of mass 2kg on its equilbrium position is 5 joules and the total energy is 9 joules when the amplitude is one meter the period of the oscillator ("in" sec) is-

The potential energy of a harmonic oscillator of mass 2 kg in its mean positioin is 5J. If its total energy is 9J and its amplitude is 0.01m, its period will be