214.2 gram of sugar syrup contains 34.2 gram of sugar. Caluculate (i) molality of the solution and (ii) mole fraction of the sugar in the syrup-

214.2 g of sugar syrup contains 34.2 g of sugar. Calculate :- Molality of the solution.

214.2 g of sugar syrup contains 34.2 g of sugar. Calculate :- Mole fraction (x) of sugar in syrup

A sugar syrup of weight 214.2 g contains 34.2 g of sugar (C_(12)H_(22)O_(11)) . Calculate (i) molal concentration (ii) mole fraction of sugar in the syrup.

A sugar syrup of weight 214.2g contains 34.2g of sugar (C_(12)H_(22)O_(11)) . Calculate (i) Molality and (ii) Mole fraction of sugar in syrup.

A sugar syrup of weight 214.2 g contains 34.2 g of sugar (C_(12) H_(22) O_(11)) . Calculate a. the molal concentration. b. the mole fraction of the sugar in the syrup.

A sugar syrup of weight 214.2 g contains 34.2 g of sugar (C_(12) H_(22) O_(11)) . Calculate a. the molal concentration. b. the mole fraction of the sugar in the syrup.

50 gram of sugar is dissolved in 2*45 kg of water. Calculate the concentration of solution.

A sugar syrup of weight 214.2 g contains 34.2 g of sugar ( molar mass = 342). The molality of the solution is :