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Find the locus of the foot of perpendicu...

Find the locus of the foot of perpendicular from the centre of the ellipse `x^2/a^2+y^2/b^2=1` on the chord joining the points whose eccentric angles differ by `pi/2`

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the locus of the foot of perpendicular drawn from the centre of the ellipse x^2+3y^2=6 on any point:

the locus of the foot of perpendicular drawn from the centre of the ellipse x^2+3y^2=6 on any point:

the locus of the foot of perpendicular drawn from the centre of the ellipse x^(2)+3y^(2)=6 on any point:

The locus of the foot of the perpendicular from the centre of the ellipse x^2 +3y^2 =3 on any tangent to it is

The locus of the foot of the perpendicular from the centre of the ellipse x^(2)+3y^(2)=3 on any tangent to it is

The locus of the foot of perpendicular drawn from the centre of the ellipse x^(2)+3y^(2)=6 on any tangent to it is-

The locus of the foot of perpendicular drawn from the centre of the ellipse x^(2)+3y^(2)=6 on any tangent to it is :