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" 6."2x-3y>6...

" 6."2x-3y>6

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In the following problems find the distance of each of the given points from the corresponding given plane: {:(" ", "Point", " Plane"), ((a), "(0,0,0)", " "3x-4y+12z=3), ((b), "(3,-2,1)", " "2x-y+2z+3=0), ((c), "(2,3,-5)", " "x+2y-2z=9), ((d), "(-6,0,0)", " "2x-3y+6z):}

The intercepts a, b of a stline on the co-ordinate axes are given by a + b=5, ab= 6 then the equation of line is 1. 2x-3y=6 2. 2x +3y -6 =0 3) 2x +3y +6 =04) 2x-3y +5=0

The area (in sq units) of the quardilateral formed by the lines 2x + 3y + 6 = 0, 2x - 3y + 6 = 0, 2x + 3y - 6 = 0 and 2x - 3y - 6 = 0 is

2x + 3y = 6 sqrt3 and 2x - 3y = 6, find the value of xy ?

The sides of a triangle are 3x+2y-6=0, 2x-3y+6=0, x+2y+2=0 . P(0,b) is a point on y-axis. If P lies on the triangle or inside the triangle then the range of b is

In the following cases, find the distance of each of the given point from the corresponding given plane (-6,0,0) : 2x-3y+6z-2 = 0

In the following case, find the distance of each of the given point from the corresponding given plane: Point (-6,0,0) Plane 2x-3y+6z-2 = 0

In the following cases, find the distance of each of the given points from the corresponding given plane. Point Plane(a) (0, 0, 0) 3x- 4y + 12 z = 3 (b) (3, -2, 1) 2x y + 2z + 3 = 0 (c) (2, 3,-5) x+2y-2z=9 (d) (-6,0,0) 2x-3y+6z-2=0