The force constant of a linear harmonic oscillator is 10 N/m. If is P.E. at a point in its path is 0.05J, its corresponding displacement is

The force constant of a simple harmonic oscillator is 3 xx 10^(6) N//m , amplitude 0.02 m has a total energy of 1250 J

When the displacement of a linear harmonic oscillator is 1//3 of its amplitude, the ratio of its total energy to its potential energy is

A linear harmonic oscillator of force constant 10^(6) N//m and amplitude 2 cm has

The displacement of a simple harmonic oscillator is x = 5 sin (pi t /3) m . Then its velocity at t =1 s , is

When the displacement of a simple harmonic oscillator is half of its amplitude, its potential energy is 3J. Its total energy is

The variation of potential energy (U) of a simple harmonic oscillator is as shown. Then force constant of the system is (PE is in joules, displacement 'x' is in mm)

A spring executes SHM with mass of 10 kg attached to it. The force constant of spring is 10 N/m. If at any instant its velocity is 40 cm/sec, the displacement will be (where amplitude is 0.5 m )

The maximum potential energy of a simple harmonic oscilator is U_("max") . The the P.E. of the oscillator when it is half way to its end point is