`Delta ABC` में, सिद्ध कीजिए कि
` a cos A + b cos B = c cos (A - B)`

In Delta ABC , a( b cos C - c cos B) =

If a cos A = b cos B then triangle ABC is

In a triangle ABC, a cos A+b cos B+ c cos C=

In a triangle ABC, a (b cos C - c cos B) =

In a triangle ABC, a (b cos C - c cos B) =

In Delta ABC , (a)/( cos A) = (b) /( cos B ) = ( c ) /( cos C ) , If b= 2 then the area of the triangle is

In Delta ABC if a: b: c = 3 : 5: 7 , then , cos A + cos B =