An ideal transformer is used to step up an alternating emf of `220V` to `4.4kV` to transmit `6.6kW` of power The current rating of the secondary is

A power transformer is used to set up an alternating e.m.f of 220V to 4.4 kV to transmits 6.6 kW of power. The primary coil has 1000 turns. What is current rating of secondary? (Assume efficiency is 100%)

A power transformer is used to step up an alternating e.m.f. of 220 V to 11kv to trannsmit 4.4 kW of power. If the primary coil has 1000 turns, what is the current rating of the secondary?(Assume 100% efficiency for the transformer)

A power transformer is used to step up an alternating e.m.f. of 220 V to 11kv to trannsmit 4.4 kW of power. If the primary coil has 1000 turns, what is the current rating of the secondary?(Assume 100% efficiency for the transformer)

A power transformer is used to step up an alternating emf of 200V to 4 KV and to transmits 5KW power. If the primary is of 1000 turns, calculate, assuming the transformer to be ideal. (i) The number of turns in the secondary (ii) The current rating of the secondary

A transformer is used to step up an alternating emf of 200V to 440V. If the primary coil has 1000 turns, calculate the number of turns in the secondary coil.

An ideal transformer is used to decrease an alternating voltage from 880 V and 220 V. If the number of turns of its primary coil is 4000, then what is that in the secondary coil?

In an ideal transformer, the voltage is stepped down from 11 kV to 220 V. If the primary current be 100 A, the current in the secondary should be ……

A current of 5 A is flowing at 220 V in the primary coil of a transformer . If the voltage produced in the secondary coil is 2200 V and 50% of power is lost, then the current in the secondary will be