The diameters of a circle pre along 2x+y-7=0 and x+3y- 11=0. Then, the equation of this circle, which also passes through (5,7) is:

The diameters of a circle are along 2x+y-7=0 and x+3y- 11=0. Then, the equation of this circle, which also passes through (5,7) is:

The diameters of a circle are along 2x+y-7=0 and x+3y-11=0. Then the equation of this circle,whichalso passes through (5,7) is

If a circle of area 16pi has two of its diameters along the line 2x - 3y + 5=0 and x + 3y - 11=0, then the equation of the circle is

The lines 2x-3y=5 and 3x-4y=7 are two diameters of a circle of area 154 sq unit. Then the equation of this circle is