ABCD a parallelogram, and `A_1 and B_1` are the midpoints of sides BC and CD, respectively. If `vec(aA)_1` `+ vec(AB)_1 = lamda vec(AC)`, then `lamda` is equal to `

ABCD a parallelogram, and A_1 and B_1 are the midpoints of sides BC and CD, respectively. If vec(A A)_1 + vec(AB)_1 = lamda vec(AC) , then lamda is equal to

ABCD is a parallelogram and A_(1) " and " B_(1) are the midpoints of sides BC and CD respectively. If vec(A""A_(1))+vec(AB_(1))=lambda/2vec(AC) , then lambda is equal to -

squareABCD is a parallelogram. (A_(1)) and B_(1) are midpoints of the sides bar(BC) and bar(AD) respectively. If vec("AA")_(1)+vec(AB)_(1)=lambda vec(AC) then lambda = …………

ABCD is a parallelogram . If P and Q are the mid-points of [BC] and [CD] respectively, show that vec AP + vec AQ=

ABCD is a parallelogram. If L and M be the middle points of BC and CD, respectively express vec(AL) and vec(AM) in terms of vec(AB) and vec(AD) . Also show that vec(AL)+vec(AM)=(3//2)vec(AC) .

If ABCD is a quadrilateral and E and F are the midpoints of AC and BD respectively, then prove that vec(AB)+vec(AD)+vec(CB)+vec(CD)=4vec(EF) .

In /_ABC if D.E.F are the midpoints of sides BC,CA, AB respectively and vec AD+(2)/(3)vec BE+(1)/(3)vec CF=kvec AC then k=

If M is the midpoint of the side vec(BC) of a triangle ABC, prove that vec(AB)+vec(AC) = 2vec(AM)

ABCD is a quadrilateral. If M and N are the mid points of the sides vec(BD) and vec(AC) , respectively. Show that vec(AB)+vec(AD)+vec(CB)+vec(CD)=4vec(NM)