Heat of formation of `2 mol` of `NH_(3)(g)` is `=90 kJ`, bond energies of `H-H` and `N-H` bonds are `435kJ` and `390 kJ mol^(-1)`, respectively. The value of the bond enegry of `N-=N` will be

Heat of formation of 2 moles of NH_(3)(g) " is" -90 kJ l bond energies of H-H and N-H bonds are 435 kJ and 390 kJ mol^(-1) respectively. The value of the bond energy of N -= N is ?

Heat of formation of 2 moles of NH_(3)(g) " is" -90 kJ l bond energies of H-H and N-H bonds are 435 kJ and 390 kJ mol^(-1) respectively. The value of the bond energy of N -= N is (1000- (x^(2) + x +25)) kJ/mol What is x ?

The bond energies of H-H and l - I bonds are 435 kJ mol^-1 and 150 kJ mol^-1 respectively. If deltaH_t^O for Hl is 26.5 kJ mol^(-1) then bond enthalpy of H-l bond is

The bond energies of H - H and I - I bonds are 435 kJ mol^-1 and 150 kJ mol^-1 respectively. If DeltaH_f^o for HI is 26.5 kJ mol^-1 then bond enthalpy of H-I bond is

Enthalpy of formation of 2mol of NH_(3)(g) is -90KJ , and DeltaH_(H-H) and DeltaH_(N-H) respectively 435KJ mol^(-1) and 390KJ mol^(-1) . The valule of DeltaH_(N-=N) is