The torque of a force `F = - 6 hat (i)` acting at a point `r = 4 hat(j)` about origin will be

The torque of a force F = -2 hat(i) +2 hat(j) +3 hat(k) acting on a point r = hat(i) - 2 hat(j)+hat(k) about origin will be

The torque of a force F = -2 hat(i) +2 hat(j) +3 hat(k) acting on a point r = hat(i) - 2 hat(k)+hat(k) about origin will be

The torque of a force F = 2 hat(i) - 3 hat(j) +5 hat(k) acting at a point whose position vector r = 3 hat(i) - 3 hat(j) +5 hat(k) about the origin is

The torque of a force F = 2 hat(i) - 3 hat(j) +5 hat(k) acting at a point whose position vector r = 3 hat(i) - 3 hat(j) +5 hat(k) about the origin is

The torque of force F = -3 hat(i)+hat(j) + 5 hat(k) acting on a point r = 7 hat(i) + 3 hat(j) + hat(k) about origin will be

The torque of force F = -3 hat(i)+hat(j) + 5 hat(k) acting on a point r = 7 hat(i) + 3 hat(j) + hat(k) about origin will be

The torque of a force vec(F)=-2hat(i)+2hat(j)+3hat(k) acting on a point vec(r )=hat(i)-2hat(j)+hat(k) about origin will be

Find the torque of a force F=-3hat(i)+2hat(j)+hat(k) acting at the point r=8hat(i)+2hat(j)+3hat(k),(iftau=rxxF)

Find the torque of a force F=-3hat(i)+2hat(j)+hat(k) acting at the point r=8hat(i)+2hat(j)+3hat(k),(iftau=rxxF)

The torque of force barF= (2 hat i -3 hat j + 4 hat k) newton acting at the point = (3 hat i + 2 hat j+ 3 hat k) metre about origin is tau (in N-m). Find x. component of tau .