Convert the equation of the plane `vecr = (hati-hatj)+lambda(-hati+hatj+2hatk)+mu(hati+2hatj+hatk)` into scalar product form.

Vector equation of the plane r = hati-hatj+ lamda(hati +hatj+hatk)+mu(hati – 2hatj+3hatk) in the scalar dot product form is

Vector equation of the plane r = hati-hatj+ lamda(hati +hatj+hatk)+mu(hati – 2hatj+3hatk) in the scalar dot product form is

Find the vector equation of the plane vecr=hati-hatj+lambda(hati+hatj+hatk)+mu(hati-2hatj+3hatk) in scalar product form. Reduce it to normal form.

The vector equation of the plane bar r=(3hati+hatj)+lambda(-hatj+hatk)+mu(hati+2hatj+3hatk) in scalar product form is

Find the vector equation of the plane vecr = 2 hati + hatj - 3 hatk + lamda ( 2hatj +hatk) + mu(5 hati + 2 hatj + hatk) in scalar product form.

The shortest distance between the lines vecr = (2hati - hatj) + lambda(2hati + hatj - 3hatk) vecr = (hati - hatj + 2hatk) + lambda(2hati + hatj - 5hatk)

Find the vector equation in scalar product form of the plane vecr=2hati-hatj+lambda(hati+2hatj+3hatk)+mu(2hati-hatj-3hatk) .

Find the vector equation of the following plane in product form vecr = ( hati-hatk)+lambda(hati+2hatj)+mu(hati+3hatj-hatk) .