If `y =a + bx ^(2),a,b` arbitary constnats, then

y= ax + bx^(2)

If y=a+ bx^(2) , where a, b are constants, then

If y=a+ bx^(2) , where a, b are constants, then

If y=a+bx^(2) , where a, b are arbitrary constants, then

If Cos ^(-1) (( x ^(2) - y ^(2))/(x ^(2) + y ^(2)))=k (a constnat), then (dy)/(dx) =

Show what y=ae^(-3x)+b, where a and b are arbitary constants, is a solution of the differential equation (d^(2)y)/(dx^(2))+3(dy)/(dx)=0

The differential equation for the family of circle x ^(2) + y ^(2) - 2ay =0 where a is an arbitary constant is :

Find the differential equation whose general solution is ax^(2) + by = 1 , where a and b are arbitary constants.

Obtain the differentiaal equation by eliminating the arbitary constants form the following equations(i) y^2=a(b-x)(b+x)