`0=b^(2)+7b-60`

solve and check y^(2)-11by-60b^(2)=0

Factorise : 4a^(2) - 49b^(2) + 2a - 7b

If in A B C , side a , b , c are in A.P. then B > 60^0 (b) B<60^0 Blt=60^0 (d) B=|A-C|

If in A B C , side a , b , c are in A.P. then B > 60^0 (b) B<60^0 Blt=60^0 (d) B=|A-C|

If in o+ABC, side a,b,c are in A.P.then B>60^(0)(b)B<60^(@)B<=60^(0)(d)B=|A-C|

If in A B C , side a , b , c are in A.P. then (a) B > 60^0 (b) B<60^0 (c) Blt=60^0 (d) B=|A-C|

If A and B are acute angles such that 2 cos A*cot B-2cos A-cot B+1=0, "then" : (A,B)-= A) (45^(@),60^(@)) B) (60^(@),45^(@)) C) (30^(@),60^(@)) D) (45^(@),30^(@))

In a triangle ABC,a=4,b=3,/_A=60^(@) then c is root of the equation c^(2)-3c-7=0 (b) c^(2)+3c+7=0(c)c^(2)-3c+7=0(d)c^(2)+3c-7=0

If a,b are roots of 3x^(2)-4x-2=0, then value of 3a^(2)+7b-(2)/(b) is equal to (a) (16)/(3) (b) (34)/(3)(c)(17)/(5)(d)(28)/(5)

If an a triangle A B C ,(2cosA)/a+(cosB)/b+(2cosC)/c=a/(b c)+b/(a c), find the /_A= (a) 90^0 (b) 60^0 (c) 30^0 (d) none of these