sin^(8)A-cos^(8)A=(sin^(2)A-cos^(2)A)(1-2sin^(2)A*cos^(2)A)

prove that sin^(8)x-cos^(8)x=(sin^(2)x-cos^(2)x)(1-2sin^(2)x cos^(2)x)

Show that : sin^8 A-cos^8 A = (sin^2 A - cos^2 A) (1-2 sin^2 A*cos^2 A)

int(sin^(8)x-cos^(8)x)/(1-2sin^(2)xcos^(2)x)dx

int(sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx

int(sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx=

int (sin^(8)x-cos^(8)x)/(1-2sin^(2)x cos^(2)x)dx =

Prove that: (sin A + cos A)/(sin A - cos A) + (sin A - cos A)/(sin A + cos A) = (2)/(sin^(2)A-cos^(2)A)=(2)/(2sin^(2)A-1)=(2)/(1-2 cos^(2)A) .

Prove the following identities: (sin+cos A)/(sin A-cos A)+(sin-cos A)/(sin A+cos A)=(2)/(sin^(2)A-cos^(2)A)=(2)/(2sin^(2)A-1)=(2)/(1-2cos^(2)A)

Prove that (sin^(2)3A)/(sin^(2)A)-(cos^(2)3A)/(cos^(2)A)=8cos2A